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Chemistry · CHEMICAL BONDING AND MOLECULAR STRUCTURE

हिन्दी

Although nitrogen is more electronegative than hydrogen and fluorine is more electronegative than nitrogen, the dipole moment of \( \text{NH}_3 \) (\( 4.90 \times 10^{-30}\text{ C m} \)) is greater than that of \( \text{NF}_3 \) (\( 0.80 \times 10^{-30}\text{ C m} \)). This is because:

  1. \( \text{NF}_3 \) is trigonal planar whereas \( \text{NH}_3 \) is pyramidal.
  2. The bond angle in \( \text{NH}_3 \) is smaller than that in \( \text{NF}_3 \).
  3. In \( \text{NH}_3 \), the orbital dipole of the lone pair reinforces the resultant \( \text{N}-\text{H} \) bond dipole, whereas in \( \text{NF}_3 \), it opposes the resultant \( \text{N}-\text{F} \) bond dipole.
  4. Nitrogen has two lone pairs in \( \text{NH}_3 \) but only one in \( \text{NF}_3 \).

Correct answer · Option 3

In \( \text{NH}_3 \), the orbital dipole of the lone pair reinforces the resultant \( \text{N}-\text{H} \) bond dipole, whereas in \( \text{NF}_3 \), it opposes the resultant \( \text{N}-\text{F} \) bond dipole.

Explanation

In \( \text{NH}_3 \), the lone pair orbital dipole adds to the resultant dipole moment of the three \( \text{N}-\text{H} \) bonds, whereas in \( \text{NF}_3 \), it opposes the resultant dipole moment of the three \( \text{N}-\text{F} \) bonds.
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