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Physics · SYSTEMS OF PARTICLES AND ROTATIONAL MOTION

हिन्दी

A uniform L-shaped thin lamina of mass \( 3\text{ kg} \) consists of three identical squares of side \( 1\text{ m} \) with its centre of mass located at \( (\frac{5}{6}\text{ m}, \frac{5}{6}\text{ m}) \). If the square corresponding to the region \( [0, 1]\times[1, 2] \) is removed, what is the new position of the centre of mass of the remaining two squares?

  1. \( (\frac{1}{2}\text{ m}, \frac{1}{2}\text{ m}) \)
  2. \( (1\text{ m}, \frac{1}{4}\text{ m}) \)
  3. \( (\frac{3}{4}\text{ m}, \frac{1}{2}\text{ m}) \)
  4. \( (1\text{ m}, \frac{1}{2}\text{ m}) \)

Correct answer · Option 4

\( (1\text{ m}, \frac{1}{2}\text{ m}) \)

Explanation

The removed square \( C_3 \) has mass \( 1\text{ kg} \) and centre at \( (\frac{1}{2}, \frac{3}{2}) \). The remaining system has mass \( 2\text{ kg} \): \( X = \frac{3(5/6) - 1(1/2)}{2} = \frac{5/2 - 1/2}{2} = 1\text{ m} \), and \( Y = \frac{3(5/6) - 1(3/2)}{2} = \frac{5/2 - 3/2}{2} = \frac{1}{2}\text{ m} \).
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