Chemistry · PYQ NEET UG 2017

It is because of inability of \( \text{ns}^2 \) electrons of the valence shell to participate in bonding that

1. A
   \( \text{Sn}^{2+} \) is reducing while \( \text{Pb}^{4+} \) is oxidising
2. B
   \( \text{Sn}^{2+} \) is oxidising while \( \text{Pb}^{4+} \) is reducing
3. C
   \( \text{Sn}^{2+} \) and \( \text{Pb}^{2+} \) are both oxidising and reducing
4. D
   \( \text{Sn}^{4+} \) is reducing while \( \text{Pb}^{4+} \) is oxidising