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Physics · SYSTEMS OF PARTICLES AND ROTATIONAL MOTION

हिन्दी

The ratio of the radius of gyration of a thin uniform circular disc of radius \( R \) about an axis passing through its centre and perpendicular to its plane to that of a uniform solid sphere of radius \( R \) about its diameter is:

  1. A
    \( \sqrt{\frac{4}{5}} \)
  2. B
    \( \sqrt{\frac{2}{5}} \)
  3. C
    \( \sqrt{\frac{5}{4}} \)
  4. D
    \( \sqrt{\frac{5}{2}} \)
View Answer & Solution

Correct answer · Option C

\( \sqrt{\frac{5}{4}} \)

Explanation

For circular disc about perpendicular axis: \( k_{\text{disc}} = \sqrt{\frac{1}{2}R^2} = \frac{R}{\sqrt{2}} \). For solid sphere about diameter: \( k_{\text{sphere}} = \sqrt{\frac{2}{5}R^2} = R\sqrt{\frac{2}{5}} \). Thus \( k_{\text{disc}} / k_{\text{sphere}} = \frac{R/\sqrt{2}}{R\sqrt{2/5}} = \sqrt{\frac{5}{4}} \).
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