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Physics · MOTION IN A STRAIGHT LINE
हिन्दीA drunkard walking in a narrow lane takes 5 steps forward and 3 steps backward, followed again by 5 steps forward and 3 steps backward, and so on. Each step is \( 1\text{ m} \) long and requires \( 1\text{ s} \). How long does the drunkard take to fall into a pit \( 13\text{ m} \) away from the start?
Correct answer · Option 3
\( 37\text{ s} \)
Explanation
In 1 cycle (8 s), net distance covered = 5 - 3 = 2 m. In 4 cycles (32 s), distance covered = 8 m. In the next 5 steps forward (5 s), distance covered = 8 + 5 = 13 m (reaches pit). Total time = 32 s + 5 s = 37 s.
