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Chemistry · PYQ NEET UG 2018

हिन्दी

The compound \( \text{C}_7\text{H}_8 \) undergoes the following reactions: \( \text{C}_7\text{H}_8 \xrightarrow{3\text{Cl}_2/\Delta} \text{A} \xrightarrow{\text{Br}_2/\text{Fe}} \text{B} \xrightarrow{\text{Zn/HCl}} \text{C} \) The product 'C' is

  1. m-bromotoluene
  2. o-bromotoluene
  3. 3-bromo-2,4,6-trichlorotoluene
  4. p-bromotoluene

Correct answer · Option 1

m-bromotoluene

Explanation

Toluene with \( 3\text{Cl}_2/\Delta \) gives benzotrichloride (A). Bromination with \( \text{Br}_2/\text{Fe} \) gives meta-bromobenzotrichloride (B) due to the meta-directing \( -\text{CCl}_3 \) group. Reduction with \( \text{Zn/HCl} \) converts \( -\text{CCl}_3 \) back to \( -\text{CH}_3 \), yielding m-bromotoluene.
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