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Chemistry · EQUILIBRIUM

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Which of the following statements regarding the action of a catalyst in a reversible reaction is correct?

  1. It lowers the activation energy of both forward and reverse reactions by the same amount.
  2. It shifts the equilibrium position toward the product side.
  3. It increases the numerical value of the equilibrium constant \( K_c \).
  4. It appears in the expression of the equilibrium constant.

Correct answer · Option 1

It lowers the activation energy of both forward and reverse reactions by the same amount.

Explanation

A catalyst provides a new reaction pathway and lowers the activation energy for both forward and reverse reactions by the same amount without altering the equilibrium constant.

Related questions

Given below are two statements:\n Statement I: Chemical equilibrium can be attained from either direction, whether starting with pure reactants or pure products.\n Statement II: The Law of Chemical Equilibrium and Law of Mass Action was proposed by Cato Maximillian Guldberg and Peter Waage in 1864. \nIn the light of the above statements, choose the most appropriate answer from the options given below:→For a 0.10 M aqueous solution of a diprotic acid \( \text{H}_2\text{X} \), the ionization constants are \( K_{a_1} = 4.0 \times 10^{-5} \) and \( K_{a_2} = 1.6 \times 10^{-11} \). The concentration of divalent anion \( [\text{X}^{2-}] \) at equilibrium is:→When \( \text{HCl} \) gas is passed through a saturated solution of \( \text{NaCl} \), pure \( \text{NaCl} \) precipitates out while impurities like \( \text{MgSO}_4 \) and \( \text{Na}_2\text{SO}_4 \) remain dissolved. The underlying reason for this phenomenon is:→In the equilibrium \( \text{Fe}^{3+}(\text{aq}) + \text{SCN}^-(\text{aq}) \rightleftharpoons [\text{Fe}(\text{SCN})]^{2+}(\text{aq}) \) (deep red), what happens to the red colour intensity upon the addition of oxalic acid \( (\text{H}_2\text{C}_2\text{O}_4) \) and why?→
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