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Physics · PYQ NEET UG 2021
हिन्दीAn inductor of inductance L, a capacitor of capacitance C and a resistor of resistance 'R' are connected in series to an ac source of potential difference 'V' volts as shown in figure. Potential difference across L, C and R is 40 V, 10 V and 40 V, respectively. The amplitude of current flowing through LCR series circuit is \( 10\sqrt{2} \) A. The impedance of the circuit is:
Correct answer · Option 3
\( 5\,\Omega \)
Explanation
Total voltage \( V = \sqrt{V_R^2 + (V_L - V_C)^2} = \sqrt{40^2 + (40 - 10)^2} = 50\text{ V} \). Peak current \( I_0 = 10\sqrt{2}\text{ A} \), rms current \( I_{rms} = 10\text{ A} \). Impedance \( Z = \frac{V_{rms}}{I_{rms}} = \frac{50}{10} = 5\,\Omega \).
