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Physics · MOTION IN A PLANE
हिन्दीA particle moves in a plane from initial position vector \( \mathbf{r}_1 = (2\hat{i} + 3\hat{j})\text{ m} \) to final position vector \( \mathbf{r}_2 = (6\hat{i} + 6\hat{j})\text{ m} \). The magnitude of the displacement vector of the particle is:
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Correct answer · Option D
\( 5\text{ m} \)
Explanation
Displacement vector \( \Delta \mathbf{r} = \mathbf{r}_2 - \mathbf{r}_1 = (6-2)\hat{i} + (6-3)\hat{j} = 4\hat{i} + 3\hat{j}\text{ m} \). Its magnitude is \( |\Delta \mathbf{r}| = \sqrt{4^2 + 3^2} = 5\text{ m} \).
