OnlineCBT
Physics · SYSTEMS OF PARTICLES AND ROTATIONAL MOTION
हिन्दीA flywheel rotating at 1200 rpm is subjected to a constant retarding torque. It decelerates uniformly and comes to rest after completing 250 revolutions. The magnitude of its angular acceleration is:
Correct answer · Option 3
\( \frac{16\pi}{5}\text{ rad/s}^2 \)
Explanation
\( \omega_0 = \frac{2\pi \times 1200}{60} = 40\pi\text{ rad/s} \). Displacement \( \theta = 250 \times 2\pi = 500\pi\text{ rad} \). Using \( \omega^2 = \omega_0^2 - 2\alpha\theta \implies 0 = (40\pi)^2 - 2\alpha(500\pi) \implies \alpha = \frac{1600\pi^2}{1000\pi} = \frac{16\pi}{5}\text{ rad/s}^2 \).
