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Chemistry · PYQ NEET UG 2019(1)

हिन्दी

Which is the CORRECT thermal stability order for \( \text{H}_2\text{E} \) (\( \text{E} = \text{O, S, Se, Te and Po} \))?

  1. \( \text{H}_2\text{O} < \text{H}_2\text{S} < \text{H}_2\text{Se} < \text{H}_2\text{Te} < \text{H}_2\text{Po} \)
  2. \( \text{H}_2\text{Po} < \text{H}_2\text{Te} < \text{H}_2\text{Se} < \text{H}_2\text{S} < \text{H}_2\text{O} \)
  3. \( \text{H}_2\text{Se} < \text{H}_2\text{Te} < \text{H}_2\text{Po} < \text{H}_2\text{O} < \text{H}_2\text{S} \)
  4. \( \text{H}_2\text{S} < \text{H}_2\text{O} < \text{H}_2\text{Se} < \text{H}_2\text{Te} < \text{H}_2\text{Po} \)

Correct answer · Option 2

\( \text{H}_2\text{Po} < \text{H}_2\text{Te} < \text{H}_2\text{Se} < \text{H}_2\text{S} < \text{H}_2\text{O} \)

Explanation

Thermal stability decreases down the group as the E-H bond length increases and bond dissociation enthalpy decreases. Therefore, \( \text{H}_2\text{O} \) is most stable and \( \text{H}_2\text{Po} \) is least stable.
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