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Physics · Electrostatic Potential

हिन्दी

Consider an electric dipole of dipole moment \( p \). At a large distance \( r \), the electrostatic potential at an angle \( \theta \) with the dipole axis is given by \( V = \frac{1}{4\pi\varepsilon_0} \frac{p \cos\theta}{r^2} \). What is the potential on the axial line of the dipole where \( \theta = 0^\circ \)?

  1. A
    \( \frac{p}{4\pi\varepsilon_0 r^2} \)
  2. B
    \( -\frac{p}{4\pi\varepsilon_0 r^2} \)
  3. C
    Zero
  4. D
    \( \frac{p}{4\pi\varepsilon_0 r} \)

Correct answer · Option A

\( \frac{p}{4\pi\varepsilon_0 r^2} \)

Explanation

For \( \theta = 0^\circ \), \( \cos(0^\circ) = 1 \), so \( V = \frac{p}{4\pi\varepsilon_0 r^2} \).
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