OnlineCBT
Physics · LAWS OF MOTION
हिन्दीMatch List-I with List-II: List-I List-II A Linear Momentum I \( \text{kg m s}^{-1} \) B Newton's Second Law II \( \vec{F} = \frac{d\vec{p}}{dt} \) C Impulse III \( \int \vec{F} dt \) D Newton's First Law IV \( \vec{F}_{\text{net}} = 0 \implies \vec{a} = 0 \) Choose the correct answer from the options given below:
Match List-I with List-II:
| List-I | List-II | ||
|---|---|---|---|
| A | Linear Momentum | I | \( \text{kg m s}^{-1} \) |
| B | Newton's Second Law | II | \( \vec{F} = \frac{d\vec{p}}{dt} \) |
| C | Impulse | III | \( \int \vec{F} dt \) |
| D | Newton's First Law | IV | \( \vec{F}_{\text{net}} = 0 \implies \vec{a} = 0 \) |
Choose the correct answer from the options given below:
Correct answer · Option 3
A-I, B-II, C-III, D-IV
Explanation
Linear momentum has unit kg m s⁻¹ (A-I). Newton's second law is F = dp/dt (B-II). Impulse is integral of F dt (C-III). Newton's first law states zero net force implies zero acceleration (D-IV).
