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Physics · MOTION IN A STRAIGHT LINE

हिन्दी

A stone is thrown vertically upward with a speed of \( 20\text{ m s}^{-1} \) from the top of a tower of height \( 60\text{ m} \). The ratio of the magnitude of displacement to the total distance covered by the stone when it reaches the ground is: (Take \( g = 10\text{ m s}^{-2} \))

  1. \( \frac{1}{2} \)
  2. \( \frac{2}{3} \)
  3. \( \frac{3}{4} \)
  4. \( \frac{3}{5} \)

Correct answer · Option 4

\( \frac{3}{5} \)

Explanation

Max height above tower \( h = \frac{u^2}{2g} = \frac{400}{20} = 20\text{ m} \). Total distance = \( 20 + 20 + 60 = 100\text{ m} \). Magnitude of displacement = \( 60\text{ m} \). Ratio = \( \frac{60}{100} = \frac{3}{5} \).
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