OnlineCBT Logo OnlineCBT
⚲
हिन्दी
OnlineCBT Logo OnlineCBT
⚲

Physics · MOTION IN A STRAIGHT LINE

हिन्दी

Match List-I with List-II regarding the nature of position-time graphs: List-I List-II A Curve bending upwards I Zero velocity (at rest) B Curve bending downwards II Positive acceleration C Straight line inclined to time axis III Zero acceleration (constant velocity) D Straight line parallel to time axis IV Negative acceleration Choose the correct answer from the options given below:

Match List-I with List-II regarding the nature of position-time graphs:


List-I List-II
A Curve bending upwards I Zero velocity (at rest)
B Curve bending downwards II Positive acceleration
C Straight line inclined to time axis III Zero acceleration (constant velocity)
D Straight line parallel to time axis IV Negative acceleration

Choose the correct answer from the options given below:

  1. A-(I), B-(IV), C-(III), D-(II)
  2. A-(IV), B-(II), C-(I), D-(III)
  3. A-(II), B-(III), C-(IV), D-(I)
  4. A-(II), B-(IV), C-(III), D-(I)

Correct answer · Option 4

A-(II), B-(IV), C-(III), D-(I)

Explanation

A curve bending upwards indicates positive acceleration (A-II). A curve bending downwards indicates negative acceleration (B-IV). A straight inclined line has constant slope, meaning zero acceleration (C-III). A horizontal line parallel to time axis has zero slope, meaning zero velocity (D-I).

Related questions

A particle moves along a straight line such that its position \( x \) at time \( t \) is given by \( x = t^3 - 6t^2 + 9t + 5 \). At what time(s) is the velocity of the particle zero?→Match List-I with List-II for motion under gravity (ball thrown vertically upward with initial speed \( v_0 \)): List-I List-II A Time taken to reach peak height I \( v_0 \) B Maximum height reached above launch point II \( \frac{2 v_0}{g} \) C Total time of flight to return to launch level III \( \frac{v_0}{g} \) D Speed upon returning to launch level IV \( \frac{v_0^2}{2g} \) Choose the correct answer from the options given below:→Match List-I with List-II regarding graph features in one-dimensional motion: List-I List-II A Position-time curve concave upwards (\( d^2x/dt^2 > 0 \)) I Net displacement over time interval B Position-time curve concave downwards (\( d^2x/dt^2 < 0 \)) II Motion with negative acceleration turning back after stopping C v-t graph with negative slope crossing time axis III Motion with positive acceleration (\( a > 0 \)) D Area under v-t graph between \( t_1 \) and \( t_2 \) IV Motion with negative acceleration (\( a < 0 \)) Choose the correct answer from the options given below:→A particle moves along a straight line with uniform acceleration \( a \). Its velocities at two points A and B are \( v_A = 10 \text{ m/s} \) and \( v_B = 30 \text{ m/s} \) respectively. Calculate the velocity of the particle as it passes through the midpoint C of the segment AB.→
OnlineCBT

Our mission is "To educate students and help them excel in competitive exam preparation to the best of their potential. To impart good values in students and develop their overall exam readiness."

Useful Link
Important Pages
Courses & Practice
Contact
Address

Plot No 10, Dholigumti, Panditpura Road, Bandikui, Dausa(Raj) 303313

Contact

+91 7877547686

 E-mail

onlinecbtportal@gmail.com

 Helpline Number

+91 7877547686
Share
Click To Download
Get it on Google Play

ऐप डाउनलोड करने
के लिए Google Play पर
उपलब्ध है

Terms of Use | Privacy Policy | Cookie Policy | Disclaimer | Editorial Policy | Fact Check | Corrections | DMCA | Ad Choices

Copyright © 2026 - OnlineCBT.in. All Rights Reserved.

WhatsApp Chat