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Physics · PYQ NEET UG 2018

हिन्दी

A block of mass \( m \) is placed on a smooth inclined wedge ABC of inclination \( \theta \) as shown in the figure. The wedge is given an acceleration 'a' towards the right. The relation between a and \( \theta \) for the block to remain stationary on the wedge is

  1. \( a = \frac{g}{\cos \theta} \)
  2. \( a = \frac{g}{\sin \theta} \)
  3. \( a = g \cos \theta \)
  4. \( a = g \tan \theta \)

Correct answer · Option 4

\( a = g \tan \theta \)

Explanation

Balancing forces in the non-inertial frame of the wedge, pseudo force \( ma \) acts horizontally leftwards. For the block to remain stationary, \( ma \cos \theta = mg \sin \theta \), which gives \( a = g \tan \theta \).
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