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Physics · PYQ NEET UG 2017
हिन्दीThe two nearest harmonics of a tube closed at one end and open at other end are \( 220\text{ Hz} \) and \( 260\text{ Hz} \). What is the fundamental frequency of the system?
Correct answer · Option 2
\( 20\text{ Hz} \)
Explanation
The difference between two consecutive harmonics in a closed pipe is equal to \( 2\nu_0 \), where \( \nu_0 \) is the fundamental frequency. Thus, \( 2\nu_0 = 260 - 220 = 40\text{ Hz} \), so \( \nu_0 = 20\text{ Hz} \).
