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Physics · MOTION IN A STRAIGHT LINE
हिन्दीA body released from rest under gravity falls freely through height \( h \). It covers a distance \( h_1 \) in the first second and a distance \( h_2 \) in the second second. Taking \( g = 9.8\text{ m s}^{-2} \), what is the ratio \( h_1 : h_2 \)?
Correct answer · Option 3
\( 1 : 3 \)
Explanation
For free fall from rest, distance in \( n^{\text{th}} \) second is \( h_n = \frac{1}{2} g (2n - 1) \). For \( n = 1 \), \( h_1 = 0.5 g \). For \( n = 2 \), \( h_2 = 1.5 g \). Thus \( h_1 : h_2 = 1 : 3 \).
