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Physics · PYQ NEET UG 2020

हिन्दी

In a guitar, two strings A and B made of same material are slightly out of tune and produce beats of frequency \( 6\text{ Hz} \). When tension in B is slightly decreased, the beat frequency increases to \( 7\text{ Hz} \). If the frequency of A is \( 530\text{ Hz} \), the original frequency of B will be:

  1. 524 Hz
  2. 536 Hz
  3. 537 Hz
  4. 523 Hz

Correct answer · Option 1

524 Hz

Explanation

Frequency of A is \( 530\text{ Hz} \) and beat frequency is \( 6\text{ Hz} \), so original frequency of B is \( 530 \pm 6 = 536\text{ Hz} \) or \( 524\text{ Hz} \). Decreasing tension decreases frequency of B. Since beat frequency increases to \( 7\text{ Hz} \), original frequency must be \( 524\text{ Hz} \).
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