Physics · PYQ NEET UG 2020
हिन्दीIn a guitar, two strings A and B made of same material are slightly out of tune and produce beats of frequency \( 6\text{ Hz} \). When tension in B is slightly decreased, the beat frequency increases to \( 7\text{ Hz} \). If the frequency of A is \( 530\text{ Hz} \), the original frequency of B will be:
Correct answer · Option 1
524 Hz
Explanation
Frequency of A is \( 530\text{ Hz} \) and beat frequency is \( 6\text{ Hz} \), so original frequency of B is \( 530 \pm 6 = 536\text{ Hz} \) or \( 524\text{ Hz} \). Decreasing tension decreases frequency of B. Since beat frequency increases to \( 7\text{ Hz} \), original frequency must be \( 524\text{ Hz} \).