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Physics · GRAVITATION
हिन्दीIf the acceleration due to gravity on the Moon is \( \frac{1}{6} \) of that on Earth and the radius of the Moon is \( \frac{1}{4} \) of the Earth's radius, then the ratio of the escape speed on the Earth to that on the Moon is:
Correct answer · Option 4
\( 2\sqrt{6} \)
Explanation
Escape velocity is \( v = \sqrt{2gR} \). Therefore, \( \frac{v_E}{v_M} = \sqrt{\frac{g_E R_E}{g_M R_M}} = \sqrt{6 \times 4} = \sqrt{24} = 2\sqrt{6} \).
