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Chemistry · CHEMICAL BONDING AND MOLECULAR STRUCTURE

हिन्दी

The bond angles in tetrahedral \( \text{CH}_4 \), pyramidal \( \text{NH}_3 \), and bent \( \text{H}_2\text{O} \) are \( 109.5^\circ \), \( 107.0^\circ \), and \( 104.5^\circ \) respectively. By how much does each successive addition of one lone pair decrease the bond angle?

  1. \( 1.5^\circ \)
  2. \( 2.0^\circ \)
  3. \( 3.0^\circ \)
  4. \( 2.5^\circ \)

Correct answer · Option 4

\( 2.5^\circ \)

Explanation

109.5° - 107.0° = 2.5°, and 107.0° - 104.5° = 2.5°. Each lone pair causes a reduction of 2.5°.
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