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Physics · UNITS AND MEASUREMENT

हिन्दी

If Energy (\( E \)), Velocity (\( v \)), and Force (\( F \)) are chosen as the fundamental physical quantities instead of Mass (\( M \)), Length (\( L \)), and Time (\( T \)), the dimensional formula of Mass (\( M \)) in this new system will be:

  1. \( [\text{E}^1 \text{v}^{-2} \text{F}^0] \)
  2. \( [\text{E}^1 \text{v}^{-1} \text{F}^{-1}] \)
  3. \( [\text{E}^2 \text{v}^{-2} \text{F}^0] \)
  4. \( [\text{E}^1 \text{v}^2 \text{F}^{-1}] \)

Correct answer · Option 1

\( [\text{E}^1 \text{v}^{-2} \text{F}^0] \)

Explanation

Kinetic energy relation gives \( E = \frac{1}{2} M v^2 \implies [M] = [E][v]^{-2} = [E^1 v^{-2} F^0] \). Dimensionally, \( [M L^2 T^{-2}][L^{-2} T^2] = [M] \).
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