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Physics · PYQ NEET UG 2020
हिन्दीAn electron is accelerated from rest through a potential difference of \( V \) volt. If the de Broglie wavelength of the electron is \( 1.227 \times 10^{-2}\text{ nm} \), the potential difference is:
Correct answer · Option 3
\( 10^4\text{ V} \)
Explanation
Using the formula for de Broglie wavelength of an electron: \( \lambda = \frac{12.27}{\sqrt{V}}\text{ Å} = \frac{1.227}{\sqrt{V}}\text{ nm} \). Given \( \lambda = 1.227 \times 10^{-2}\text{ nm} \), we get \( \sqrt{V} = 100 \implies V = 10^4\text{ V} \).
