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Physics · GRAVITATION

हिन्दी

If \( \mathbf{r}_1 \) and \( \mathbf{r}_2 \) are the position vectors of two point masses \( m_1 \) and \( m_2 \) respectively, and \( \mathbf{r} = \mathbf{r}_2 - \mathbf{r}_1 \), then in vector notation, the gravitational force \( \mathbf{F}_{12} \) exerted on \( m_1 \) by \( m_2 \) is correctly given by:

  1. \( \mathbf{F}_{12} = -G \frac{m_1 m_2}{|\mathbf{r}|^3} \mathbf{r} \)
  2. \( \mathbf{F}_{12} = -G \frac{m_1 m_2}{|\mathbf{r}|^2} \mathbf{r} \)
  3. \( \mathbf{F}_{12} = G \frac{m_1 m_2}{|\mathbf{r}|^2} \mathbf{r} \)
  4. \( \mathbf{F}_{12} = G \frac{m_1 m_2}{|\mathbf{r}|^3} \mathbf{r} \)

Correct answer · Option 4

\( \mathbf{F}_{12} = G \frac{m_1 m_2}{|\mathbf{r}|^3} \mathbf{r} \)

Explanation

The force on \( m_1 \) due to \( m_2 \) is attractive, directed along \( (\mathbf{r}_2 - \mathbf{r}_1) = \mathbf{r} \), so \( \mathbf{F}_{12} = G \frac{m_1 m_2}{|\mathbf{r}|^2} \hat{\mathbf{r}} = G \frac{m_1 m_2}{|\mathbf{r}|^3} \mathbf{r} \).
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