The moment of the force, \( \vec{F} = 4\hat{i} + 5\hat{j} - 6\hat{k} \) at \( (2, 0, -3) \), about the point \( (2, -2, -2) \), is given by

Position vector \( \vec{r} = (2 - 2)\hat{i} + (0 - (-2))\hat{j} + (-3 - (-2))\hat{k} = 0\hat{i} + 2\hat{j} - 1\hat{k} \). Torque \( \vec{\tau} = \vec{r} \times \vec{F} = \begin{vmatrix} \hat{i} & \hat{j} & \hat{k} \ 0 & 2 & -1 \ 4 & 5 & -6 \end{vmatrix} = \hat{i}(-12 - (-5)) - \hat{j}(0 - (-4)) + \hat{k}(0 - 8) = -7\hat{i} - 4\hat{j} - 8\hat{k} \).