Physics · GRAVITATION
हिन्दीFour identical particles, each of mass \( m \), are placed at the vertices of a square of side \( l \). The gravitational potential at the centre of the square is:
Correct answer · Option 1
\( -4\sqrt{2} \frac{G m}{l} \)
Explanation
Distance of each vertex from centre is \( r = l/\sqrt{2} \). The potential is \( U(r) = -4 \frac{Gm}{l/\sqrt{2}} = -4\sqrt{2} \frac{Gm}{l} \).