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Physics · GRAVITATION

हिन्दी

Four identical particles, each of mass \( m \), are placed at the vertices of a square of side \( l \). The gravitational potential at the centre of the square is:

  1. A
    \( -4\sqrt{2} \frac{G m}{l} \)
  2. B
    \( -2\sqrt{2} \frac{G m}{l} \)
  3. C
    \( -4 \frac{G m}{l} \)
  4. D
    \( -8 \frac{G m}{l} \)
View Answer & Solution

Correct answer · Option A

\( -4\sqrt{2} \frac{G m}{l} \)

Explanation

Distance of each vertex from centre is \( r = l/\sqrt{2} \). The potential is \( U(r) = -4 \frac{Gm}{l/\sqrt{2}} = -4\sqrt{2} \frac{Gm}{l} \).
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