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Physics · MOTION IN A PLANE
हिन्दीA particle starts from the origin at \( t = 0 \) with an initial velocity \( \vec{v}_0 = 5.0\hat{i}\text{ m/s} \) and moves in the xy-plane under a constant acceleration \( \vec{a} = (3.0\hat{i} + 2.0\hat{j})\text{ m/s}^2 \). What is the y-coordinate of the particle at the instant its x-coordinate is \( 84\text{ m} \)?
Correct answer · Option 1
36 m
Explanation
x-motion: \( x = 5.0t + \frac{1}{2}(3.0)t^2 = 84 \implies 1.5t^2 + 5t - 84 = 0 \implies t = 6\text{ s} \). y-motion: \( y = \frac{1}{2}(2.0)(6)^2 = 36\text{ m} \).
