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Physics · MOTION IN A STRAIGHT LINE

हिन्दी

A particle moving along a straight line with uniform acceleration covers distance \( x_1 \) in time interval \( t \) and distance \( x_2 \) in the next equal time interval \( t \). The magnitude of acceleration of the particle is:

  1. \( \frac{x_2 + x_1}{t^2} \)
  2. \( \frac{2(x_2 - x_1)}{t^2} \)
  3. \( \frac{x_2 - x_1}{t^2} \)
  4. \( \frac{x_2 - x_1}{2t^2} \)

Correct answer · Option 3

\( \frac{x_2 - x_1}{t^2} \)

Explanation

\( x_1 = ut + \frac{1}{2}at^2 \) and total distance \( x_1 + x_2 = u(2t) + \frac{1}{2}a(2t)^2 = 2ut + 2at^2 \). Multiplying first equation by 2 gives \( 2x_1 = 2ut + at^2 \). Subtracting from total distance equation yields \( x_2 - x_1 = at^2 \implies a = \frac{x_2 - x_1}{t^2} \).
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