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Physics · PYQ NEET UG 2016(1)

हिन्दी

When a metallic surface is illuminated with radiation of wavelength \( \lambda \), the stopping potential is \( V \). If the same surface is illuminated with radiation of wavelength \( 2\lambda \), the stopping potential is \( \frac{V}{4} \). The threshold wavelength for the metallic surface is

  1. \( 5\lambda \)
  2. \( 3\lambda \)
  3. \( 4\lambda \)
  4. \( 5\lambda/2 \)

Correct answer · Option 2

\( 3\lambda \)

Explanation

Using Einstein's photoelectric equation \( eV = \frac{hc}{\lambda} - \frac{hc}{\lambda_0} \) for both cases and solving gives \( \lambda_0 = 3\lambda \).
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