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Mathematics · JEE | LIMITS AND DERIVATIVES
हिन्दीEvaluate \( \lim_{x \to 2} \frac{x^3 - 2x^2}{x^2 - 5x + 6} \).
View Answer & Solution
Correct answer · Option D
-4
Explanation
Factoring gives \( \lim_{x \to 2} \frac{x^2(x-2)}{(x-2)(x-3)} = \frac{4}{-1} = -4 \).
