Mathematics · JEE | INTEGRALS
हिन्दीEvaluate the integral \( \int \frac{dx}{\sqrt{9x - 4x^2}} \).
View Answer & Solution
Correct answer · Option C
\( \frac{1}{2} \sin^{-1}(\frac{9x-8}{9}) + C \)
Explanation
Writing \( 9x - 4x^2 = -4(x^2 - \frac{9}{4}x) = -4[(x-\frac{9}{8})^2 - (\frac{9}{8})^2] \), integration yields \( \frac{1}{2} \sin^{-1}(\frac{8x-9}{9}) + C \).