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Mathematics · JEE | INTEGRALS
हिन्दीFind \( \int \frac{e^{2x} - 1}{e^{2x} + 1} \, dx \).
View Answer & Solution
Correct answer · Option C
\( \log |e^x + e^{-x}| + C \)
Explanation
Divide numerator and denominator by \( e^x \) to get \( \int \frac{e^x - e^{-x}}{e^x + e^{-x}} dx \). Putting \( e^x + e^{-x} = t \), the integral evaluates to \( \log |e^x + e^{-x}| + C \).
