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Chemistry · PYQ NEET UG 2020
हिन्दीFind out the solubility of \( \mathrm{Ni(OH)_2} \) in \( 0.1\text{ M NaOH} \). Given that the ionic product of \( \mathrm{Ni(OH)_2} \) is \( 2 \times 10^{-15} \).
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Correct answer · Option D
\( 2 \times 10^{-13}\text{ M} \)
Explanation
Due to common ion effect, \( [\mathrm{OH^-}] \approx 0.1\text{ M} \). \( K_{sp} = [\mathrm{Ni^{2+}}][\mathrm{OH^-}]^2 \implies s(0.1)^2 = 2 \times 10^{-15} \implies s = 2 \times 10^{-13}\text{ M} \).
