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Mathematics · JEE | APPLICATION OF INTEGRALS

हिन्दी

Find the area of the region bounded by the ellipse \( \frac{x^2}{16} + \frac{y^2}{9} = 1 \).

  1. A
    \( 24\pi \)
  2. B
    \( 16\pi \)
  3. C
    \( 9\pi \)
  4. D
    \( 12\pi \)
View Answer & Solution

Correct answer · Option D

\( 12\pi \)

Explanation

For \( a = 4 \) and \( b = 3 \), the area of the ellipse \( \pi ab \) is \( \pi \times 4 \times 3 = 12\pi \).
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