Mathematics · JEE | APPLICATION OF INTEGRALS
हिन्दीFind the area of the region bounded by the ellipse \( \frac{x^2}{16} + \frac{y^2}{9} = 1 \).
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Correct answer · Option D
\( 12\pi \)
Explanation
For \( a = 4 \) and \( b = 3 \), the area of the ellipse \( \pi ab \) is \( \pi \times 4 \times 3 = 12\pi \).