Mathematics · JEE | APPLICATION OF INTEGRALS
हिन्दीFind the area of the region bounded by the line \( y = 3x + 2 \), the x-axis and the ordinates \( x = -1 \) and \( x = 1 \).
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Correct answer · Option D
\( \frac{13}{3} \)
Explanation
Splitting at root \( x = -2/3 \), absolute areas sum to \( \left| \int_{-1}^{-2/3} (3x+2)dx \right| + \int_{-2/3}^{1} (3x+2)dx = \frac{1}{6} + \frac{25}{6} = \frac{13}{3} \).