Mathematics · JEE | LIMITS AND DERIVATIVES
हिन्दीFind the derivative of \( f(x) = \frac{x + \cos x}{\tan x} \).
View Answer & Solution
Correct answer · Option A
\( \frac{(1 - \sin x)\tan x - (x + \cos x)\sec^2 x}{\tan^2 x} \)
Explanation
Applying the quotient rule to \( \frac{u}{v} \) with \( u = x + \cos x \) and \( v = \tan x \) gives \( \frac{u'v - uv'}{v^2} = \frac{(1 - \sin x)\tan x - (x + \cos x)\sec^2 x}{\tan^2 x} \).