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Mathematics · JEE | CONTINUITY AND DIFFERENTIABILITY

हिन्दी

Find the derivative of \( y = \cos^{-1}(e^x) \) with respect to \( x \).

  1. A
    \( \frac{e^x}{\sqrt{1 - e^{2x}}} \)
  2. B
    \( \frac{-e^x}{\sqrt{1 - e^{2x}}} \)
  3. C
    \( \frac{-1}{\sqrt{1 - e^{2x}}} \)
  4. D
    \( \frac{-e^x}{1 - e^{2x}} \)
View Answer & Solution

Correct answer · Option B

\( \frac{-e^x}{\sqrt{1 - e^{2x}}} \)

Explanation

By the chain rule, \( \frac{dy}{dx} = \frac{-1}{\sqrt{1 - (e^x)^2}} \cdot \frac{d}{dx}(e^x) = \frac{-e^x}{\sqrt{1 - e^{2x}}} \).
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