Physics · JEE | MOTION IN A PLANE
हिन्दीFor a given projection velocity \( v_0 \), what is the formula for the maximum horizontal range \( R_m \) of a projectile?
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Correct answer · Option B
\( R_m = \frac{v_0^2}{g} \)
Explanation
Range is maximum when \( \sin 2\theta_0 = 1 \) (i.e. \( \theta_0 = 45^\circ \)), giving \( R_m = v_0^2/g \).