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Physics · Electrostatic Potential

हिन्दी

For a linear isotropic dielectric, the polarisation vector is related to the electric field by \( \mathbf{P} = \varepsilon_0 \chi_e \mathbf{E} \). The electric susceptibility \( \chi_e \) is:

  1. A
    measured in \( \text{C}\cdot\text{m}^{-2} \)
  2. B
    a dimensionless quantity
  3. C
    measured in \( \text{V}\cdot\text{m}^{-1} \)
  4. D
    measured in \( \text{F}\cdot\text{m}^{-1} \)
View Answer & Solution

Correct answer · Option B

a dimensionless quantity

Explanation

Both \( \mathbf{P} \) and \( \varepsilon_0 \mathbf{E} \) have dimensions of surface charge density (\( \text{C}\cdot\text{m}^{-2} \)); hence, the susceptibility \( \chi_e = P/(\varepsilon_0 E) \) is dimensionless.
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