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Physics · GRAVITATION

हिन्दी

For a satellite of mass \( m \) moving in a circular orbit of radius \( r \) around the Earth, the ratio of its kinetic energy (\( K.E. \)) to its total mechanical energy (\( E \)) is:

  1. A
    \( 1 : 1 \)
  2. B
    \( 1 : 2 \)
  3. C
    \( -1 : 1 \)
  4. D
    \( -1 : 2 \)
View Answer & Solution

Correct answer · Option C

\( -1 : 1 \)

Explanation

Kinetic energy is \( K.E. = \frac{GM_E m}{2r} \) and total energy is \( E = -\frac{GM_E m}{2r} \), hence \( K.E./E = -1 \).
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