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Chemistry · CHEMICAL BONDING AND MOLECULAR STRUCTURE

हिन्दी

For an octahedral molecule \( \text{AB}_6 \) (such as \( \text{SF}_6 \)) with zero lone pairs on the central atom, calculate the ratio of the number of \( 90^\circ \) \( \text{B}-\text{A}-\text{B} \) bond angles to the number of \( 180^\circ \) \( \text{B}-\text{A}-\text{B} \) bond angles.

  1. A
    \( 3 : 1 \)
  2. B
    \( 4 : 1 \)
  3. C
    \( 6 : 1 \)
  4. D
    \( 2 : 1 \)

Correct answer · Option B

\( 4 : 1 \)

Explanation

In an octahedral geometry, there are 12 angles of \( 90^\circ \) and 3 collinear pairs giving 3 angles of \( 180^\circ \). Ratio = \( 12 / 3 = 4 : 1 \).
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