Chemistry · CHEMICAL BONDING AND MOLECULAR STRUCTURE
हिन्दीFor an octahedral molecule \( \text{AB}_6 \) (such as \( \text{SF}_6 \)) with zero lone pairs on the central atom, calculate the ratio of the number of \( 90^\circ \) \( \text{B}-\text{A}-\text{B} \) bond angles to the number of \( 180^\circ \) \( \text{B}-\text{A}-\text{B} \) bond angles.
Correct answer · Option B
\( 4 : 1 \)
Explanation
In an octahedral geometry, there are 12 angles of \( 90^\circ \) and 3 collinear pairs giving 3 angles of \( 180^\circ \). Ratio = \( 12 / 3 = 4 : 1 \).