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Chemistry · EQUILIBRIUM

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For the dimerization reaction \( 2\text{NO}_2(\text{g}) \rightleftharpoons \text{N}_2\text{O}_4(\text{g}) \) with \( \Delta H = -57.2\text{ kJ mol}^{-1} \), what change is observed in the brown colour of the gas mixture when the temperature is lowered from \( 298\text{ K} \) to \( 270\text{ K} \) in a sealed tube?

  1. A
    The brown colour intensifies because \( \text{NO}_2 \) is favoured at lower temperatures
  2. B
    There is no colour change because equilibrium constants are temperature independent
  3. C
    The brown colour turns dark yellow due to conversion into liquid \( \text{NO} \)
  4. D
    The brown colour fades because the forward exothermic reaction is favoured, forming colourless \( \text{N}_2\text{O}_4 \)
View Answer & Solution

Correct answer · Option D

The brown colour fades because the forward exothermic reaction is favoured, forming colourless \( \text{N}_2\text{O}_4 \)

Explanation

The forward reaction is exothermic (\( \Delta H < 0 \)). Lowering the temperature shifts equilibrium forward according to Le Chatelier's principle, forming colourless \( \text{N}_2\text{O}_4 \) and fading the brown colour of \( \text{NO}_2 \).
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