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Physics · JEE | Ray Optics and Optical Instruments

हिन्दी

For three media, if \( n_{32} \) is the refractive index of medium 3 with respect to medium 2 and \( n_{31} \) is that of medium 3 with respect to medium 1, then \( n_{32} \) can be expressed as:

  1. A
    \( n_{32} = \frac{n_{31}}{n_{12}} \)
  2. B
    \( n_{32} = n_{31} + n_{12} \)
  3. C
    \( n_{32} = n_{31} \times n_{12} \)
  4. D
    \( n_{32} = \frac{n_{12}}{n_{31}} \)
View Answer & Solution

Correct answer · Option C

\( n_{32} = n_{31} \times n_{12} \)

Explanation

By the principle of refractive index scaling, \( n_{32} = n_{31} \times n_{12} \).
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