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Chemistry · THERMODYNAMICS

हिन्दी

Given the standard enthalpies of formation: \( \Delta_f H^\ominus[\text{CO}(g)] = -110.53\text{ kJ mol}^{-1} \) and \( \Delta_f H^\ominus[\text{CO}_2(g)] = -393.51\text{ kJ mol}^{-1} \). The standard enthalpy change (\( \Delta_r H^\ominus \)) for the reaction \( \text{CO}(g) + \frac{1}{2}\text{O}_2(g) \rightarrow \text{CO}_2(g) \) is:

  1. A
    -282.98 kJ mol⁻¹
  2. B
    -504.04 kJ mol⁻¹
  3. C
    +282.98 kJ mol⁻¹
  4. D
    -141.49 kJ mol⁻¹
View Answer & Solution

Correct answer · Option A

-282.98 kJ mol⁻¹

Explanation

\( \Delta_r H^\ominus = \Delta_f H^\ominus(\text{CO}_2) - \Delta_f H^\ominus(\text{CO}) = -393.51 - (-110.53) = -282.98\text{ kJ mol}^{-1} \).
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