प्रिज्म से निर्गत कोण का मान ज्ञात कीजिए। कांच का अपवर्तनांक \( \sqrt{3} \) है।

From the given prism geometry, angle of incidence \( i = 60^\circ \), prism angle \( A = 60^\circ \). Using Snell's law: \( \sin i = n \sin r_1 \implies \sin 60^\circ = \sqrt{3} \sin r_1 \implies r_1 = 30^\circ \). Since \( r_1 + r_2 = A \implies r_2 = 30^\circ \). At the second surface, \( \sin e = n \sin r_2 = \sqrt{3} \sin 30^\circ = \sqrt{3} \times \frac{1}{2} = \frac{\sqrt{3}}{2} \implies e = 60^\circ \).