निम्नलिखित परिपथ में, टर्मिनल A और टर्मिनल B के बीच तुल्य धारिता है:

The circuit forms a balanced Wheatstone bridge of capacitors. The central capacitor receives no potential difference. The upper and lower branches each give \( 1\ \mu\text{F} \), so \( C_{eq} = 1 + 1 = 2\ \mu\text{F} \).