दिए गए तार्किक परिपथ के लिए, सत्यता सारणी है:

The circuit contains two NOT gates followed by a NOR gate. Thus \( Y = \overline{\overline{A} + \overline{B}} = A \cdot B \) (AND gate equivalent). The truth table for AND gate is 0,0->0; 0,1->0; 1,0->0; 1,1->1.