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Chemistry · Some Basic Concepts of Chemistry
हिन्दीHow many water molecules are present in a drop of water weighing \( 0.018\text{ g} \)?
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Correct answer · Option B
6.022 × 10²⁰
Explanation
Moles of water = \( \frac{0.018}{18} = 10^{-3}\text{ mol} \). Number of molecules = \( 10^{-3} \times 6.022 \times 10^{23} = 6.022 \times 10^{20} \).
